Recipe

Tax incidence on a linear-demand monopoly

How a tax shifts the monopolist's optimum depends entirely on whether it enters the marginal condition. A Per-Unit Tax raises MCMC; a Lump-Sum Tax does not.

  1. Classify the tax. Per-unit (paid per unit produced) → enters MC. Lump-sum, profit-tax, or fixed-cost shock → does not enter MC.
  2. For a lump-sum / profit tax, (Q∗,P∗)(Q^*, P^*) are unchanged. Just subtract the tax from profit and check the participation constraint: if post-tax profit is still positive, the firm stays.
  3. For a per-unit tax tt, replace MCMC with MC+tMC + t everywhere and re-solve. With linear demand P=A−bQP = A - bQ and linear MC =c+mQ= c + mQ: MR=A−2bQ=c+mQ+tMR = A - 2bQ = c + mQ + t, giving Q∗∗=(A−c−t)/(2b+m)Q^{**} = (A - c - t)/(2b + m).
  4. Compute the pass-through: ΔP/Δt=b/(2b+m)\Delta P / \Delta t = b / (2b + m). With constant MC (m=0m = 0), exactly half the tax is passed on. With rising MC (m>0m > 0), less than half.
  5. Tax revenue is t⋅Q∗∗t \cdot Q^{**}; firm bears (1−ΔP/Δt)⋅t(1 - \Delta P/\Delta t) \cdot t per unit; consumer bears ΔP/Δt⋅t\Delta P / \Delta t \cdot t per unit.

Common pitfalls

  • Assuming a per-unit tax is fully passed on to consumers. The monopolist optimally absorbs part of the tax — the share depends on the demand and MC slopes.
  • Treating a lump-sum tax as if it shifted price. It only shifts profit; the marginal condition MR=MCMR = MC is unchanged.
  • Forgetting the participation check. A large enough lump-sum tax (or a sufficiently negative post-tax profit at the per-unit-adjusted optimum) drives the firm to shut down.

Worked example

P=1300−5qP = 1300 - 5q, MC=50+10qMC = 50 + 10q (see EX-4 - Micro 3 Q3). Pre-tax: q∗=62.5q^* = 62.5, P∗=$987.50P^* = \$987.50. Lump-sum tax $5,000 → unchanged (q,P)(q, P); profit drops from $39,062.50 to $34,062.50, still positive. Per-unit tax $300 → MCnew=350+10qMC_{\text{new}} = 350 + 10q, q∗∗=47.5q^{**} = 47.5, P∗∗=$1,062.50P^{**} = \$1,062.50 — price rises by only $75 (25% pass-through, matching the formula 5/(2⋅5+10)=0.255/(2 \cdot 5 + 10) = 0.25).