Recipe

Lerner pricing rule (constant elasticity)

When demand has constant elasticity ∣E∣|E|, the monopolist's profit-maximising price is a one-step computation from the Lerner Index identity — no MR curve, no algebra over QQ.

  1. Read off (or compute) the marginal cost MCMC and the price elasticity ∣E∣|E|.
  2. Apply the rule: P∗=MC1−1/∣E∣\displaystyle P^* = \frac{MC}{1 - 1/|E|}.
  3. (Optional) Compute the markup ratio (Lerner Index): L=(P∗−MC)/P∗=1/∣E∣L = (P^* - MC)/P^* = 1/|E|.
  4. (Optional) If the demand curve is calibrated Q=kP−∣E∣Q = k P^{-|E|}, back out kk from any observed (P,Q)(P, Q) point, then evaluate Q∗=k(P∗)−∣E∣Q^* = k (P^*)^{-|E|} to get the new quantity.

Common pitfalls

  • The rule only applies when ∣E∣|E| is constant (i.e. demand of the form Q=kP−∣E∣Q = k P^{-|E|}). For linear demand, ∣E∣|E| varies along the curve — use the linear-demand recipe instead.
  • The rule breaks down at ∣E∣=1|E| = 1: the denominator goes to zero. With ∣E∣<1|E| < 1 the formula returns a negative price — the lecture's reminder that monopolists never operate in the inelastic region.
  • More-elastic segments always get a lower markup. If you apply the rule to two segments (e.g. business vs students) and the elastic group ends up with the higher price, recheck your arithmetic.

Worked example

Magazine: MC=$16MC = \$16, ∣E∣=5|E| = 5 (see EX-5 - Micro 3 Q1a). P∗=16/(1−1/5)=16/(4/5)=$20P^* = 16 / (1 - 1/5) = 16 / (4/5) = \$20. Markup ratio L=1/5=20%L = 1/5 = 20\%. Calibrated at (P,Q)=(40,1000)(P, Q) = (40, 1000) gives k=1.024×1011k = 1.024 \times 10^{11}, so Q∗=k/205=32,000Q^* = k / 20^5 = 32{,}000 copies.